An ellipse with major axis 4 and minor axis 2 touches both the coordinate axes, then locus of its focus is
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Statement-1 : Let focus of ellipse are ( α , β ) and (h, k)
Product of length of perpendicular dropped from focus on any tangent is b 2
∴ h α = 1 ⇒ α = 
k β = 1 ⇒ β = 
Now distance between focii is 2 ae
∴ (h – α ) 2 + (k + β ) 2 =
= 12
+
= 12
After simplification (h 2 + k 2 ) (1 + h 2 k 2 ) = 16h 2 k 2
Hence the locus (x 2 + y 2 ) (1 + x 2 y 2 ) = 16x 2 y 2
Statement-2 Standard result.
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