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CGP EDU Academic Team
Published on: August 14, 2026
The equation of a hyperbola with co-ordinate axes as principal axes, if the distances of one of its vertices from the foci are 3 & 1 can be :
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a,b)Let one of the vertices be (a, 0)
Focii are (ae, 0) & (– ae, 0)
given that ae – a = 1 & ae + a = 3
⇒ 2ae = 4 ⇒ ae = 2
∴ a = 1 ⇒ e = 2
∴ using e 2 = 1 + 
⇒ b 2 = 3
∴ Required hyperbola is
∴ 
– 
= 1 ⇒ 3x 2 – y 2 = 3
Again, one more possibility is
e 2 = 1 + 
⇒ b 2 = 
∴ Hyperbola will be x 2 – 3y 2 + 3 = 0
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