Published by:
CGP EDU Academic Team
Published on: August 13, 2026
A tangent is drawn to the curve x 2 + 2x – 4ky + 3 = 0 at a point whose abscissa is 3. This tangent is perpendicular to x + 3 = 2y. Find the area bounded by the curve, this tangent and ordinate x = – 1
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(
) sq. units.
Sol. x 2 + 2x – 4ky + 3 = 0

2x + 2 – 4k
= 0
put x = 3,
= – 2
6 + 2 + 8k = 0
k = – 1
y = –
(x 2 + 2x + 3)
Tangent is 4x + 2y – 3 = 0
Area =
= 
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
(i)Find the area bounded by x² + y² − 2 x = 0 and y = sin in the upper half of the circle.
(ii)Fin…
Find the area of the region bounded by the curve y 2 = 2y – x and the y-axis.
Find the area bounded by the y-axis and the curve x = e y sin π y, y = 0, y = 1.
(i) Find the area bounded in the first quadrant between the ellipse and the line 3x + 4y =12
(ii) …
Compute the area of the figure bounded by straight lines x = 0, x = 2 and the curves y = 2 x and y…
Let f(x) = . Show that area bounded by y = f(x), y = f(c), x = 0 and x = a, 0 < c < a < is minimu…