Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let 
lie on the plane px - qy +z=5, for some p, q 
R. The shortest distance of the plane from the origin is:
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
B
(2, -1, -3) satisfy the given plane.
So 2p + q = 8 .... (i)
Also given line is perpendicular to normal plane so
3p + 2q-l = 0 ....(ii)
p=15,q = -22
Eq. of plane 15x - 22y + z - 5 = 0
its distance from origin = 
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