Published by:
CGP EDU Academic Team
Published on: August 14, 2026
A point P moves so that the sum of squares of its distances from the points (1, 2) and (-2, 1) is 14. Let f(x, y) = 0 be the locus of P, which intersects the x-axis at the points A, B and the y-axis at the point C, D . Then the area of the quadrilateral ACBD is equal to
A
B
C
D
9
Text Solution
Verified by ExpertsThe correct answer is:
B
(x-1) 2 + (y-2) 2 + (x + 2) 2 + (y-1) 2 =14
X 2 +y 2 +X-3y-2 = 0
Put x = 0
Put y=0
x 2 +x - 2 = 0
(x + 2)(x- l)= 0
Area 
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