Published by:
CGP EDU Academic Team
Published on: August 13, 2026
A tower PQ stands on a horizontal ground with base Q on the ground. The point R divides the tower in two parts such that QR = 15 m. If from a point A on the ground the angle of elevation of R is 60° and the part PR of the tower subtends an angle of 15° at A, then the height of the tower is :
A
5(2 
+ 3) m
+ 3) m
B
5( 
+ 3) m
+ 3) m
C
10( 
+1) m
+1) m
D
10(2 
+1) m
+1) m
Text Solution
Verified by ExpertsThe correct answer is:
A
= tan 60° …(1)
= tan 75° …(2)
So, PQ = 5(2 
+3) m
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