Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let the function f(x) = 2x 2 - log e x, x > 0, be decreasing in (0, a) and increasing in (a, 4). A tangent to the parabola y 2 = 4ax at a point P on it passes through the point (8a, 8a - 1) but does not pass through the point 
. If the equation of the normal at P is 
, then 
is equal to-
Text Solution
Verified by ExpertsThe correct answer is:
45
(45)
f '(x) = 4x - 
Let P(x 1 ,y 1 ) be any point on y 2 = 4ax
P(8,4) as P(2, 2) rejected Equation of normal at P.
y-4 = -4(x-8)
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