Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let p(x) be a polynomial of degree 4 having extremum at x = 1, 2 and 
= 2. Then the value of p(2) is
Text Solution
Verified by ExpertsThe correct answer is:
0
(0)
Sol. p(x) = ax 4 + bx 3 + cx 2 + dx + e
p ′ (x) = 4ax 3 + 3bx 2 + 2cx + d
p ′ (1) = 4a + 3b + 2c + d = 0 .....(i)
p ′ (2) = 32 a + 12 b + 4c + d = 0 .....(ii)
= 2
= 2
c + 1 = 2, d = 0, e = 0
c = 1
Now equation (i) and (ii) are
4a + 3b = – 2 and 32 a + 12 b = – 4
⇒ a = 
and b = – 1
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