Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let ω be the complex number cos 
+ i sin 
. Then the number of distinct complex numbers z satisfying 
= 0 is equal to
Text Solution
Verified by ExpertsThe correct answer is:
1
(1)
Sol. ω = cos 
+ i sin 
R 1 → R 1 + R 2 + R 3
= 0
⇒ z 
= 0
z = 0
= 0
(z + ω 2 – ω)(z + ω – ω 2 ) – (1 – ω)(1 – ω 2 ) = 0
z 2 = 0
only one solution
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