Paragraph for Questions (i) to (ii)
The mass of nucleus 
is less than the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of mass m 1 and m 2 only if (m 1 + m 2 ) < M. Also two light nuclei of masses m 3 and m 4 can undergo complete fusion and form a heavy nucleus of mass M ’ only if (m 3 + m 4 ) > M ’ . The masses of some neutral atoms are given in the table below:
1.007825u | 2.014102u | 3.016050u | 4.002603u | ||||
6.015123u | 7.016004u | 69.925325u | 81.916709u | ||||
151.919803u | 205.974455 | 208.980388u | 209.982876u |
(i) The correct statement is
can emit an alpha particle 5319
can emit a proton. 5422
and 
can undergo complete fusion. (ii) The kinetic energy (in keV) of the alpha particle, when the nucleus 
at rest undergoes alpha decay, is 5818
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)
So no 
-decay is possible
So, this reaction is not possible
So, this reaction is possible
So this reaction is not possible
(ii)
Q=(209.982876-4.002603-205.97455)C 2
=5.422MeV
from conservation of momentum
4K 1 =206K 2
K 1 + K 2 = 5.422
K 1 = 5.319 MeV = 5319 KeV
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