A thermodynamic system is taken from an initial state i with internal energy U i = 100 J to the final state f along two different paths iaf and ibf, as schematically shown in the figure. The work done by the system along the paths af, ib and bf are W af = 200 J, W ib = 50 J and W bf = 100 J respectively. The heat supplied to the system along the path iaf, ib and bf are Q iaf , Q ib and Q bf respectively. If the internal energy of the system in the state b is U b = 200 J and Q iaf = 500 J, the ratio Q bf / Q ib is

Text Solution
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(2)U b = 200 J, U i =100 J
Process iaf
Process | W(in Joule) | (in Joule) | Q(in Joule) |
ia | 0 | ||
af | 200 | ||
Net | 300 | 200 | 500 |

Process ibf
Process | W(in Joule) | (in Joule) | Q(in Joule) |
ib | 100 | 50 | 150 |
bf | 200 | 100 | 300 |
Net | 300 | 150 | 450 |

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