Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2014-Paper-2 SECTION – 2 : Comprehension type (Only One O…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2014-Paper-2 Single Correct MCQ
Published on: August 12, 2026

SECTION – 2 : Comprehension type (Only One Option Correct)

This section contains 3 paragraphs, each describing theory, experiments, data etc. Six questions relate to the three paragraphs with two questions on each paragraph. Each question has only one correct answer among the four given options

A
, 8 larger mean free path for X as compared to that of Y.
B
, 12 larger mean free path for Y as compared to that of X.
C
and 16 increased collision frequency of Y with the inert gas as compared to that of X with the inert gas.
D
. Paragraph for Questions (i) & (ii) X and Y are two volatile liquids with molar weights of 10 g mol -1 and 40 g mol -1 respectively. Two cotton plugs, one soaked in X and the other soaked in Y, are simultaneously placed at the ends of a tube of length L = 24 cm, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of 300 K. Vapours of X and Y react to form a product which is first observed at a distance d cm from the plug soaked in X. Take X and Y to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours. (i) The value of d in cm (shown in the figure), as estimated from Graham ’ s law, is 20 (ii) The experimental value of d is found to be smaller than the estimate obtained using Graham ’ s law. This is due to increased collision frequency of X with the inert gas as compared to that of Y with the inert gas.

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The correct answer is:
CHECK THE SOLUTION.

(i)

d = 48 – 2d

3d = 48

d = 16cm

(ii) As the collision frequency increases then molecular speed decreases than the expected.

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