Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2015-Paper-2 A closed vessel with rigid walls contains 1 …
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2015-Paper-2 Numeric Response
Published on: August 14, 2026

A closed vessel with rigid walls contains 1 mol of and 1 mol of air at 298 K. Considering complete decay of to , the ratio of the final pressure to the initial pressure of the system at 298 K is

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The correct answer is:
9

(9)In conversion of to , 8 - particles and 6 particles are ejected.

The number of gaseous moles initially = 1 mol

The number of gaseous moles finally = 1 + 8 mol; (1 mol from air and 8 mol of 2He4)

So the ratio = 9/1 = 9

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