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CGP EDU Academic Team
Published on: August 14, 2026
Suppose that all the terms of an arithmetic progression (A.P.) are natural numbers. If the ratio of the sum of the first seven terms to the sum of the first eleven terms is 6 : 11 and the seventh term lies in between 130 and 140, then the common difference of this A.P. is
Text Solution
Verified by ExpertsThe correct answer is:
9
(9)Let seventh term be ‘ a ’ and common difference be ‘ d ’
Given 
Hence, 130 < 15d < 140
d = 9
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