A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure P t = 10 5 Pa and volume V t = 10 -3 m 3 changes to a final state at P f = (1/32) x 10 5 Pa and V f = 8 x 10 -3 m 3 in an adiabatic quasi-static process, such that P 3 V 5 = constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at P i followed by an isochoric (isovolumetric) process at volume V f . The amount of heat supplied to the system in the two-step process is approximately
Text Solution
Verified by ExpertsC
monoatomic gas
From first law of thermodynamics
H = W +
U
W = P i
V
= 700J
U = nC v
T

So, H = W +
U =588 J
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