Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Integrate: 
Text Solution
Verified by ExpertsThe correct answer is:
5
+ 
tan − 1 
+ C
Sol: 5 x 2 − 12 = l (x 2 − 6 x + 13) + m (2 x − 6) + n
equating co-efficient l = 5; m = 15; n = 13
⇒ Ι = 
+ 
dx + 13 
Now vc Ι 1 = 
tan − 1 
; I 2 = − 
& I 3 = 13 
d θ ,
where x − 3 = 2 tan θ, = 
cos 2 θ ) d θ = 
= 
+ 
. 
= 
tan − 1 
+ 
. 
⇒ Ι = Ι 1 + Ι 2 + Ι 3 = 
+ 
tan − 1 
+ C
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