Published by:
CGP EDU Academic Team
Published on: August 12, 2026
Let f(x) = x 3 − x 2 + x + 1 and g(x) =,
then:
Text Solution
Verified by ExpertsThe correct answer is:
C
f(x) = x 3 − x 2 + x + 1
f '(x) = 3x 2 − 2x + 1 > 1 , 
f(x) is strictly increasing
So g(x) =
= 
g(1) = f(1) = 1 – 1 + 1 + 1 = 2 = 
= 3 – 1 + 1 = 3
g(x) is neither continous nor differentiable at x = 1
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