Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let g: R → R be a differentiable function with g(0) = 0, g'(0) = 0 and g'
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a,d)
Sol. g(0) = 0, g ′ (0) = 0 g ′ ≠ 0
h(x) = e |x|
=
, 
=
= g ′ (0) = 0
=
=
g ′ (0) = 0
= 1 &
So h(x) is non derivable. at x = 0
Now
=

R(f ′ (h(x))) =
=
= g ′
= – g ′ Hence
is non derivable at x = 0
Since x = 0 is repeated root of g(x) So
is differetiable at x = 0
hence ,
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Let L = , a > 0. If L is finite, then
If = 2b sin 2 θ , b > 0 and θ ∈ (– π , π ], then the value of θ is
Let f : R → R be a function such that f(x + y) = f(x) + f(y), ∀ x, y ∈ R . If f(x) is differentiabl…
If f(x) = , then
Let f : (0, 1) → R be defined by f(x) = , where b is a constant such that 0 < b < 1. Then
If = 4, then
and h(x) = e |x| for all x ∈ R. Let (foh)(x) denote f(h(x)) and (hof)(x) denote h(f(x)). Then which of the following is(are) true? f is differentiable at x = 0