Published by:
CGP EDU Academic Team
Published on: August 11, 2026
If AD, BE and CF are the medians of a Δ ABC, then (AD 2 + BE 2 + CF 2 ) : (BC 2 + CA 2 + AB 2 ) is equal to
Text Solution
Verified by ExpertsThe correct answer is:
C
AD 2 =
(2b 2 + 2c 2 – a 2 ),
BE 2 =
(2c 2 + 2a 2 – b 2 ) and
CF 2 =
(2a 2 + 2b 2 – c 2 ) ∴
= 
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If α , β , γ are the respective altitudes of a triangle ABC, prove that
(i) + + =
(ii) =
If in an acute angled Δ ABC, line joining the circumcentre and orthocentre is parallel to side AC, …
A regular hexagon & a regular dodecagon are inscribed in the same circle. If the side of the dodeca…
If D is the mid point of CA in triangle ABC and Δ is the area of triangle, then show that
tan ( ∠ A…
If in a triangle ABC, the line joining the circumcentre and incentre is parallel to BC, then cos B…
In a Δ ABC, if AB = 5 cm, BC = 13 cm and CA = 12 cm, then the distance of vertex ‘A’ from the side …