Internal bisector of ∠ A of triangle ABC meets side BC at D. A line drawn through D perpendicular to AD intersects the side AC at E and the side AB at F. If a, b, c represent sides of Δ ABC, the
cos 
sin 
Text Solution
Verified by ExpertsA
(a,b,c,d)We have Δ ABC = Δ ABD + Δ ACD
⇒ 
bc sin A = 
c AD sin 
+ 
b × AD sin 
⇒ AD = 
Again AE = AD sec 
= 
⇒ AE is HM of b and c.
EF = ED + DF = 2DE = 2 × AD tan 
= 
× cos 
× tan 
= 
sin 
As 
and DE = DF and AD is bisector ⇒ Δ AEF is isosceles.
Hence A, B, C and D are correct answers.
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems