Published by:
CGP EDU Academic Team
Published on: August 12, 2026
In Δ ABC, prove that a 2 (s –a) + b 2 (s – b) + c 2 (s – c) = 4R Δ 
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
L.H.S. = 
[a 2 (b + c – a) + b 2 (c + a – b) + c 2 (a + b – c)]
= 
[a(b 2 + c 2 – a 2 ) + b(c 2 + a 2 – b 2 ) + c (a 2 + b 2 – c 2 )]
= 
(2abc cosA + 2abc cosB + 2abc cosC)
= abc 
= 4R Δ 
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