Published by:
CGP EDU Academic Team
Published on: August 13, 2026
In an acute angled triangle ABC, r + r 1 = r 2 + r 3 and ∠ B > 
, then prove that b + 3c < 3a < 3b + 3c
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
r – r 2 = r 3 – r 1 ⇒ 
or 
or 
= 
⇒ tan 2 
= 
But 
∈ 
. Therefore
tan 2 
∈ 
⇒ 
< 
< 1
or b < 3a – 3c < 3b
b + 3c < 3a < 3b + 3c
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