The hypotenuse BC = a of a right-angled triangle ABC is divided into n equal segments where n is odd. The segment containing the midpoint of BC subtends angle α α at A. Also h is the altitude of the triangle through A. Prove that 
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Let LN be the segment of the side BC containing its midpoint M. We have
. Let AH be the altitude from A on BC, with AH = h. Also ∠ ∠ LAN = α α . Let ∠ ∠ NAH = θ θ ⇒ ⇒ ∠ ∠ HAL = α α - θ θ .From Δ Δ AMH, we have
. Also 

Now 

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