Published by:
CGP EDU Academic Team
Published on: August 12, 2026
For what triplets of real numbers (a, b, c) with a ≠ 0 the function
f(x) =
is differentiable for all real x?
Text Solution
Verified by ExpertsThe correct answer is:
A
f(x) = 
f(x) should be continous at x =1
it gives a+b+c =1
f(x) should be differentiable at x= 1
it gives 2a+b=1 ⇒ b =1–2a c= 1–a–b= a
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