Solve
(i)tan 2 θ – (1 +
) tan θ +
= 0
(ii)4 cos θ – 3 sec θ = 2 tan θ
(iii)tan x . tan
. tan
=
.
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(i)tan 2 θ – (1 +
) tan θ +
= 0
After factorization we get
⇒ tan θ = 1,
⇒ θ = n π +
, n π +
.
(ii)4 cos θ – 3 sec θ = 2 tan θ ⇒ 4 cos θ –
=
⇒ 4 cos2 θ – 3 = 2 sin θ
⇒ 4 – 4 sin 2 θ – 3 = 2 sin θ ⇒ 4 sin 2 θ + 2 sin θ – 1 = 0
⇒ sin θ =
=
=
⇒ sin θ =
,
= –cos 36 º , sin 18 º
= –sin 54 º , sin 18 º = sin
, sin
⇒ θ = n π + (–1)n
or n π – (–1)n
.
(iii)tan x . tan
. tan
=
⇒
= 
⇒
=
⇒
⇒ 
⇒ 
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