One mole of a monatomic ideal gas undergoes four thermodynamic processes as shown schematically in the PV-diagram below. Among these four processes, one is isobaric, 3P 0 one is isochoric, one is isothermal and one is adiabatic.
Match the processes mentioned in List-1 with the corresponding statements in List-II.
LIST-I LIST-II
P. In process I 1. Work done by the gas is zero
Q. In process II 2. Temperature of the gas remains unchanged
R. In process III 3. No heat is exchanged between the gas and its surroundings
S. In process IV 4. Work done by the gas is 6P 0 V 0
4; Q 
3; R 
1; S 
2
1; Q 
3; R 
2; S 
4
3; Q 
4; R 
1; S 
2
3; Q 
4; R 
2; S 
1
Text Solution
Verified by ExpertsC
Process 1 is adiabatic process, hence Q = 0
Process 2 is isobaric, hence W = P. 
V = 6 P 0 V 0
Process 3 is isochoric, hence W = 0
Process 4 is isothermal
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