Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2019-Paper-1 SECTION 3 (Maximum Marks: 18) • This section…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2019-Paper-1 Numeric Response
Published on: August 11, 2026

SECTION 3 (Maximum Marks: 18)

• This section contains SIX (06) questions. The answer to each question is a NUMERICAL VALUE.

• For each question, enter the correct numerical value of the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer. If the numerical value has more than two decimal places, truncate/round-off the value to TWO decimal places.

• Answer to each question will be evaluated according to the following marking scheme:

Full Marks : +3 If ONLY the correct numerical value is entered;

Zero Marks : 0 In all other cases.

A block of weight 100 N is suspended by copper and steel wires of same cross sectional area 0.5 cm 2 and, length m and 1 m, respectively. Their other steel wire ends are fixed on a ceiling as shown in figure. The angles subtended by copper and steel wires with ceiling are 30° and 60°, respectively. If elongation in copper wire is and elongation in steel wire is , then the ratio is ________

[Young's modulus for copper and steel are 1 x 10 11 N/m 2 and 2 x 10 11 N/m 2 , respectively.]

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Text Solution

Verified by Experts
The correct answer is:
2

(2)

T s sin30° = T c sin60°

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