Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2019-Paper-1 For the following reaction, the equilibrium …
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2019-Paper-1 Numeric Response
Published on: August 14, 2026

For the following reaction, the equilibrium constant K c at 298 K is 1.6 x 10 17

Fe 2+ (aq) + S 2- (aq) FeS(s)

When equal volumes of 0.06 M Fe 2+ (aq) and 0.2 M S 2- (aq) solutions are mixed, the equilibrium concentration of Fe 2+ (aq) is found to be Y x 10 -17 M. The value of Y is..........

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Verified by Experts
The correct answer is:
8.93

(8.93)

Fe 2+ (aq)+ S 2- (aq) FeS(s) K c =1.6x10 17

Initial 0.06 M 0.2 M

After mixing 0.03 M 0.1 M

? 0.07M

or

or 8.93x10 -17 =Yx10 -17

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