Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The figure formed by the lines 2x + 5y + 4 = 0, 5x + 2y + 7 = 0, 2x + 5y + 3 = 0 and 5x + 2y + 6 = 0 is
Text Solution
Verified by ExpertsThe correct answer is:
C
Distance between lines AB & CD = Distance between lines AD and BC
⇒ ABCD is a rhombus, also side AD is not perpendicular to DC hence not a square.
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The vertices of a triangle OBC are O(0,0) B(–3,–1) and C(–1,–3). Find the equation of line parallel…
A variable line, drawn through the point of intersection of the straight lines = 1 and = 1, meet…
From the vertices A, B, C of a triangle ABC, perpendiculars AD, BE, CF are drawn to any straight li…
A triangle is formed by the lines whose equations are AB : x + y – 5 = 0, BC : x + 7y – 7 = 0 and …
The coordinates of the feet of from the vertices of a Δ on the opposite sides are (20, 25), (8, 16…
Let P is any point inside the triangle ABC of side lengths 6, 5, 5 units and p 1 , p 2 , p 3 be the…