Let O be the origin and OP and OQ be the tangents to the circle x 2 + y 2 -6x + 4y + 8 = 0 at the points P and Q on it. If the circumcircle of the triangle OPQ passes through the point 
then 
value of a is
Text Solution
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The given information can be represented in the form of the diagram below.
Since angle in a semicircle is a right angle.
Hence, the other circle will be passing through the centre of the first circle.
The two ends of diameter of the circle is O(0,0) and C(3, -2).
Hence, the required equation of circle is (x - 0)(x - 3)+(y - 0)(y -(-2))= 0
x 2 + y 2 - 3x + 2y = 0
Put 
in the above equations 
Therefore this is the correct option.
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