PART II: CHEMISTRY
SECTION 1 (Maximum Marks: 18)
• This section contains SIX (06) questions.
• The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, BOTH INCLUSIVE.
• For each question, enter the correct integer corresponding to the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer,
• Answer to each question will be evaluated according to the following marking scheme:
Full Marks : +3 If ONLY the correct integer is entered;
Zero Marks : 0 If the question is unanswered;
Negative Marks : -1 In all other cases.
The 1 st , 2 nd , and the 3 rd ionization enthalpies, 
, and I 3 , of four atoms with atomic numbers n, n + 1, n + 2, and n + 3, where n < 10, are tabulated below. What is the value of n?
Atomic Number | Ionization Enthalpy (kJ/mol) | ||
I1 | I2 | I3 | |
n | 1681 | 3374 | 6050 |
n+1 | 2081 | 3952 | 6122 |
n+2 | 496 | 4562 | 6910 |
n+3 | 738 | 1451 | 7733 |
Text Solution
Verified by Experts9
(9)
Since I.E. of Na is 495.8 kJ mol -1 , so (n + 2) should be 11.
n + 2=11, So n = 9
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