The structure of a peptide is given below:
If the absolute values of the net charge of the peptide at pH = 2, pH =6, and pH = 11 are |z 1 |, |z 2 |, and |z 3 |, respectively, then what is |z 1 | + |z 2 | + |z 3 | ?
Text Solution
Verified by Experts5
(5)
At pH = 2 (highly acidic), the structure of the peptide will be as shown below.
So, |Z 1 | = 2
At pH = 6 it will exist as neutral or zwitter-ion structure as shown below.
So, according to this condition, |Z 2 | = 0
At pH = 11 (highly basic), the given peptide will exist as:
So, |Z 3 | = |-3| = 3
|Z 1 | + |Z 2 | + |Z 3 | =2 + 0 + 3 = 5
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