SECTION 2 (Maximum Marks: 24)
• This section contains SIX (06) questions. The answer to each question is a NUMERICAL VALUE.
• For each question, enter the correct numerical value of the answer using the mouse and the on-screen virtual numeric keypad in the place designated to enter the answer, If the numerical value has more than two decimal places, truncate/round-off the value of TWO decimal places.
• Answer to each question will be evaluated according to the following marking scheme.
Full Marks : +4 If ONLY the correct numerical value is entered;
Zero Marks : 0 In all other cases.
A solution of 0.1 M weak base
BH + + A - . 
Text Solution
Verified by Experts03.00
(03.00)
From the graph, it is clear, that the equivalence point is reached at a titre value of 6 mL i.e. when 6 mL of HA are added base is completely neutralized. So it will be half neutralized at titre value of 3mL;when 3 mL of HA is added, 'B' is half- neutralized. So at this stage it will form a best buffer.
i.e. pOH = pK b = 3 L
So, pK b of weak base = 3
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