Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 Tin is obtained from cassiterite by reductio…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 Numeric Response
Published on: August 13, 2026

Tin is obtained from cassiterite by reduction with coke. Use the data given below to determine the minimum temperature (in K) at which the reduction of cassiterite by coke would take place.

At 298 K; f H° (SnO 2 (s)) = -581.0 kJ mol -1 , f H 0 (CO 2 (g)) = - 394.0 kJ mol -1 ,

S° (SnO 2 (s)) = 56.0 J K -1 mol -1 , S 0 (Sn(s)= 52.0 J K -l mol -l

S° (C (s)) = 6.0 J K -1 mol -1 , 5° (CO 2 (g))= 210.0 J K -l mol -1 ,

Assume that the enthalpies and the entropies are temperature independent.

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Text Solution

Verified by Experts
The correct answer is:
935

(935)

SnO 2 (s) + C(s) Sn(s) + CO 2 (g)

= -394.0 + 581 = 187 kJmol -1 S

0 =210 + 52-6-56=200 Jmol -1 K -1

Equilibrium temperature (T) eq = = 935 K

So, T > 935 K (for spontaneity)

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