PART I: PHYSICS SECTION 1 • This section contains FOUR (04)…

Maths JEE - Advanced Previous Year Paper JEE-Advanced-2021-Paper-1 Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 12, 2026

PART I: PHYSICS

SECTION 1

• This section contains FOUR (04) questions.

• Each question has FOUR options

, 3.07 cm

, 3.11 cm

and 3.15 cm

. ONLY ONE of these four options is the correct answer. • Four each question, choose the option corresponding to the correct answer. • Answer to each question will be evaluated according to the following marking scheme: Full Mark +3 If only the correct option is chosen; Zero Marks 0 If none of the options is chosen (i.e. the question is unanswered) Negative Marks -1 In all other cases. The smallest division on the main scale of a Vernier calipers is 0.1 cm. Ten divisions of the Vernier scale correspond to nine divisions of the main scale. The figure below on the left shows the reading of this calipers with no gap between its two jaws. The figure on the right shows the reading with a solid sphere held between the jaws. The correct diameter of the sphere is

3.17 cm

Text Solution

Verified by Experts

The correct answer is:

Least count = (0.1) = 0.01 cm

Zero error = -0.1 + 0.06 = -0.04 cm

Final reading = 3.1 + 0.01 x 1 = 3.11 cm

So correct measurement = 3.11 + 0.04 = 3.15 cm

──────────────────────────────────────────────────────────────────────────────────────────

Previous Question Next Question

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Share this question

Text Solution

Prepare Smarter with CGP Edu

Write a Review

Commentary

Student Reviews

Similar Questions