Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2021-Paper-2 A source, approaching with speed u towards t…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2021-Paper-2 Single Correct MCQ
Published on: August 14, 2026

A source, approaching with speed u towards the open end of a stationary pipe of length L, is emitting a sound of frequency f s . The farther end of the pipe is closed. The speed of sound in air is v and f 0 is the fundamental frequency of the pipe. For which of the following combination(s) of u and fs, will the sound reaching the pipe lead to a resonance?

A
u = 0.8v and f s = f 0
B
u = 0.8v and f s = 2f 0
C
u = 0.8v and f s = 0.5f 0
D
u = 0.5v and f s =1.5f 0

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Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(a, d)

Natural frequency of closed pipe

f=(2n+l)f 0

f 0 is fundamental frequency

n = 0, 1,2,...........

frequency of source received by pipe

For resonance

F' = f

If u = 0.8 v

f s = f 0

for n = 2 pipe can be in resonance

Hence, option is correct.

If u = 0.8v f s = 2f 0

Not possible

If u = 0.5v, f s = 1.5ft

For n=1 f=3f 0

pipe can be in resonance

Hence, option is correct.

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