A circle passing through the point 
in the first quadrant touches the two coordinate axes at the points A and B. The point P is above the line AB. The point Q on the line segment AB is the foot of perpendicular from P on AB. If PQ is equal to 11 units, then the value of 
is________
Text Solution
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Let the equation of circle touching both the coordinate axis be,
(x - r) 2 + (y-r) 2 = r 2 which passes through 
So, ( 
-r) 2 + ( 
-r) 2 = r 2 .......
Also equation of line AB : x + y = r
Let Q(h,k),
Now using the formula of foot of perpendicular,
Now using the distance formula we get,
{from equation , 
}
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