The foci of a hyperbola are (±2, 0) and its eccentricity is 
. A tangent, perpendicular to the line 2x + 3y = 6, is drawn at a point in the first quadrant on the hyperbola. If the intercepts made by the tangent on the x- and y-axes are a and b respectively, then |6a| + |5b| is equal to
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The given equation of hyperbola is 
The tangent is perpendicular to 2x + 3y = 6.
Slope of tangent is 
Equation of tangent, m = 
Equation of tangent is y = mx 
( 
Tangent is in 1 st quadrants 
C < 0)
Converting the equation into intercept form:
Hence this is the required option.
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