For a 1, b
Z and |a-b|
10, let the angle between the plane P: ax + y - z = b and the line
L: x-1 = a - y = z + 1 be cos -1
If the distance of the point (6, -6,4) from the plane P is
then a 4 +b 2 is equal to
Text Solution
Verified by ExpertsA
Given
For a,b
Z and |a-b|
10. let the angle between the plane P : ax+y-z = b and the line L : x-1 = a - y = z + 1 be 
Now rewriting the equation of line we get.

Now let, 
Now we know that.
Angle between plane and line is given by,



3(a 2 + 4-4a)=8(a 2 +2)
5a 2 + 12a + 4 = 0
So a =
, a = -2
Hence a = -2 
So. the equation of plane will be.
P: -2x+y-z-b = 0
Now given, distance of point (6, -6,4) from plane is= 



So, b = -4 
Hence, a 4 + b 2 = 16 + 16 = 32
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