The plane, passing through the points (0, -1, 2) and (-1, 2, 1) and parallel to the line passing through (5, 1, -7) and (1, -1, -1), also passes through the point
Text Solution
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Let A(0,-l, 2) & B(-1,2,1) and given plane is parallel to line passing through (5,1, 7) & (1,-1,-1)
So, normal vector to the plane is given by,
Equation of plane
16(x- 0) + 10(y + 1) + 14 (z- 2) = 0
8x + 5y + 7z = 9
Now satisfying the points from option in the plane we get,
(-2,5,0) only point which satisfy the plane.
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