Home Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 Two identical non-conducting solid spheres o…
Maths JEE - Advanced Previous Year Paper JEE-Advanced-2020-Paper-2 Single Correct MCQ
Published on: August 13, 2026

Two identical non-conducting solid spheres of same mass and charge are suspended in air from a common point by two non-conducting, massless strings of same length. At equilibrium, the angle between the strings is a. The spheres are now immersed in a dielectric liquid of density 800 kg m -3 and dielectric constant 21. If the angle between the strings remains the same after the immersion, then

A
electric force between the spheres remains unchanged
B
electric force between the spheres reduces
C
mass density of the spheres is 840 kg m -3
D
the tension in the strings holding the spheres remains unchanged

Share this question

For Instagram sharing, use “Apps” on mobile or copy the link.

Text Solution

Verified by Experts
The correct answer is:
CHECK THE SOLUTION.

(a, c)

So, T 2 will decrease

──────────────────────────────────────────────────────────────────────────────────────────

Prepare Smarter with CGP Edu

Get practice questions, solutions, and test series in one place.

Write a Review

Share your experience with this question and solution.

Commentary

Send your comment, doubt, correction, or feedback to admin.

Student Reviews

What students say about this solution

No reviews yet. Be the first to write a review.

Similar Questions

Explore conceptually related problems

CG
CGP Question Assistant Question Bank + AI Help
Hi! Type your question or upload one screenshot. First I will search related questions from CGP Edu Question Bank. If none match, type YES and I will solve it with AI.
Upload only one screenshot at a time. Flow: Question Bank first → If not matched, type YES for AI solution.