Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The Inverse trigonometric equation sin –1 x = 2 sin –1 α , has a solution for
A
– 
< α < 
< α <
B
all real values of α
C
| α | ≤ 
D
| α | ≥ 
Text Solution
Verified by ExpertsThe correct answer is:
C
Given that , sin –1 x = 2 sin –1 α
Since , – 
≤ sin –1 x ≤ 
⇒ – 
≤ 2 sin –1 α ≤ 
⇒ – 
≤ sin –1 α ≤ 
⇒ sin 
≤ α ≤ sin 
⇒ – 
≤ α ≤ 
⇒ | α | ≤ 
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