Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The least positive integer x, which satisfies the inequality 
(x 2 – 10x + 22) > 0 is equal to
Text Solution
Verified by ExpertsThe correct answer is:
D
Case -I
log 2 (x/2) > 1 ⇒ x 2 – 10 x + 22 > 1
⇒ x>4 & x ∈ (– ∞ ,3) ∪ (7 , ∞ )
⇒ x ∈ (7 , ∞ )
Case- II
0 < log 2 (x/2) < 1 ⇒ 0 < x 2 – 10 x + 22 < 1
⇒ x ∈ (2,4) & x ∈ (3,7) and x 2 – 10 x + 22 > 0
⇒ no integer exist among above inequalities ⇒ positive integer x is 8
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