Published by:
CGP EDU Academic Team
Published on: August 14, 2026
In (0, 6 π ), the number of solutions of the equation tan θ + tan 2 θ + tan 3 θ = tan θ .tan2 θ .tan3 θ is are
Text Solution
Verified by ExpertsThe correct answer is:
B
tan θ + tan 2 θ + tan 3 θ – tan θ tan 3 θ tan 2 θ = 0 ...(1)
⇒ tan( θ + 2 θ + 3 θ ) = 0 ⇒ tan 6 θ = 0 ⇒ 6 θ = n π ⇒ θ = 
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Match the set P in column one with its super set Q in column II
Column – Ι (set P) Column – ΙΙ (set…
If ≤ 4, then the least and the highest values of 4x 2 are:
If ≥ 1 and is an odd integer then number of possible values of α is
If log a b = 2; log b c = 2 and log 3 c = 3 + log 3 a then (a + b + c) equals
The sum of the solutions of the equation 9 x – 6 · 3 x + 8 = 0 is
The expression: reduces to