Published by:
CGP EDU Academic Team
Published on: August 12, 2026
The solution of |cosx| = cosx – 2sinx is
A
x = n π , n ∈ Ι
B
x = n π + 
, n ∈ Ι
, n ∈ Ι
C
x = n π + (–1)n 
, n ∈ Ι
, n ∈ Ι
D
x = (2n + 1) π + 
, n ∈ Ι
, n ∈ Ι
Text Solution
Verified by ExpertsThe correct answer is:
D
|cos x| = cos x – 2 sin x
Case-I : cos x ≥ 0 ⇒ cos x = cos x – 2 sin x ⇒ sin x = 0 ⇒ x = n π = 2m π or (2m + 1) π
As cos x ≥ 0 ∴ x = 2m π
Case-II : cos x < 0 ⇒ –cos x = cos x – 2 sin x ⇒ tan x = 1 ⇒ x = n π + 
⇒ x = 2m π + 
or (2m + 1) π + 
As cos x < 0 ∴ x = (2m + 1) π + 
.
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