Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If tanA + tan B + tan C = tan A. tan B. tan C, then
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a,b,c)
tan A + tan B + tan C – tan A tan B tan C = 0
⇒ sin A cos B cos C + sinB cos A cos C + sinC cos A cos B – sin A sin B sin C = 0
⇒ sin (A + B + C) = 0
⇒ A + B + C = n π , n ∈ Ι
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If sin θ = and θ lies in the second quadrant, find the value of sec θ + tan θ .
Column-IColumn-II(A) tan 9° − tan 27° − tan 63° + tan 81° (P)1(B)cosec 10° – sec 10°(Q)2(C)…
Column-IColumn-II(A)If for some real x, the equation x + = 2 cos θ holds, then cos θ is equal to…
Column-IColumn-II(A)Number of solutions of sin2θ + 3 cos θ = 3(P)0 in [– π, π](B)Number of solution…
In a triangle ABC if tan A < 0 then:
If sin α = 1/2 and cos θ = 1/3, then the values of α + θ (if θ , α are both acute) will lie in the …