Published by:
CGP EDU Academic Team
Published on: August 11, 2026
4 sin 4 x + cos 4 x = 1 if
A
x = n π ; (n ∈ I )
B
x = n π ± 
cos–1 
; (n ∈ I )
cos–1 ; (n ∈ I )
C
x = 
; (n ∈ I )
; (n ∈ I )
D
x = – n π ; (n ∈ I )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a,b,d)
4 sin 4 x + (1 – sin 2 x) 2 = 1 ⇒ 5 sin 4 x – 2 sin 2 x = 0
sin 2 x (5 sin 2 x – 2) = 0 ⇒ sin 2 x = 0 ; sin 2 x = 
⇒ x = n π ; n ∈ Ι or cos 2x = 1 – 2 sin 2 x = 1 – 
∴ cos 2x = 
= cos α ∴ 2x = 2n π ± α ∴ x = n π ± 
cos–1 
; n ∈ Ι
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