Published by:
CGP EDU Academic Team
Published on: August 13, 2026
A, is a (3×3) diagonal matrix having integral entries such that det(a) = 120, number of such matrices is 10n. Then n is :
Text Solution
Verified by ExpertsThe correct answer is:
36
(36)
Sol. given 
⇒ abc = 120 = 2 3 ×3 1 ×5 1
Case - I All are Positive = 5 C 2 × 3 C 2 × 3 C 2 = 90
Case - I one Positive and two negative
= 3 × ( 5 C 2 × 3 C 2 × 3 C 2 ) = 270
So number of possible matrices = 90 + 270 = 360
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