Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The number of values of k for which the linear equations
4x + ky + 2z = 0
kx + 4y + z = 0
2x + 2y + z = 0
posses a non-zero solution is :
Text Solution
Verified by ExpertsThe correct answer is:
B
Δ = 
= 0 ⇒ 8 – k(k – 2) – 2(2k – 8) = 0
⇒ 8 – k 2 + 2k – 4k + 16 = 0 ⇒ – k 2 – 2k + 24 = 0
⇒ k 2 + 2k – 24 = 0 ⇒ (k + 6)(k – 4) = 0 ⇒ k = – 6, 4
Number of values of k is 2
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