A line 
= 
= 
intersects the plane x – y + 2z + 2 = 0 at point A. The equation of the straight line passing through A lying in the given plane and at minimum inclination with the given line is/are
= 
= 
= 
= 
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
(a,b,c,d)
2r + 1 – (3r + 2) + 2 (4r + 3) + 2 = 0 ⇒ 7r + 7 = 0 ⇒ r = – 1
∴ A(–1, –1, – 1) required line will be projection of given line in the plane foot of ⊥ of P will be on D
= 
= 
= – 
; 
= 
= 
= 
x = 
; y = 
; z = 
⇒ 
= 
= 
⇒ 
= 
+1 = 
+1
Also , 
= 
= 
⇒ 
= 
and 
= 
⇒ 5x – y + 4 = 0 = 2y – 5z – 3
also (5x – y + 4) + (2y – 5z – 3) = 0 = 2y – 5z – 3 ⇒ 5x + y – 5z + 1 = 0 = 2y – 5z – 3
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